(X^2)/0.52-x=(1.1*10^-8)

Solution for (X^2)/0.52-x=(1.1*10^-8) equation:

(X^2)/0.52-X=(1.1*10^-8)

We move all terms to the left:

(X^2)/0.52-X-((1.1*10^-8))=0

We add all the numbers together, and all the variables

X^2/0.52-1X-8-1.1E=0

We multiply all the terms by the denominator


X^2-1X*0.52-8*0.52-(1.1E)*0.52=0

We add all the numbers together, and all the variables

X^2-1X*0.52-8*0.52-(2.9901100113049)*0.52=0

We add all the numbers together, and all the variables

X^2-1X*0.52-5.7148572058785=0

Wy multiply elements

X^2-0.52X-5.7148572058785=0

a = 1; b = -0.52; c = -5.7148572058785;
Δ = b2-4ac
Δ = -0.522-4·1·(-5.7148572058785)
Δ = 23.129828823514
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.52)-\sqrt{23.129828823514}}{2*1}=\frac{0.52-\sqrt{23.129828823514}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.52)+\sqrt{23.129828823514}}{2*1}=\frac{0.52+\sqrt{23.129828823514}}{2}
$